Webscala > val textFile = spark. read. textFile ("README.md") textFile: org.apache.spark.sql.Dataset [String] = [value: string] You can get values from Dataset directly, by calling some actions, or transform the Dataset to get a new one. For more details, please read the API doc. WebAny string can be converted to a regular expression using the .r method. Scala 2 Scala 3 import scala.util.matching. Regex val numberPattern: Regex = " [0-9]" .r numberPattern.findFirstMatchIn ( "awesomepassword") match { case Some (_) => println ( "Password OK" ) case None => println ( "Password must contain a number" ) }
Scala String replace() method with example - GeeksforGeeks
WebAccording to Ignacio Alorre, if you want to replace others chars into string: def replaceChars (str: String) = str.map (c => if (c == '0') ' ' else if (c =='T') '_' else if (c=='-') '_' else if (c=='Z') '.' … WebAccording to the official Scala string interpolation documentation, when you precede your string with the letter s, you’re creating a processed string literal. This example uses the “ s string interpolator,” which lets you embed variables inside … man united wfc
Quick Start - Spark 3.2.4 Documentation
WebHere is what you are after, note that I had to add the +1on the indexes because from your example your range is inclusive, while the String functions in Scala are not.. def desiredFunction(string: String, startIndex: Int, endIndex: Int, replaceFunc: (String) => String) = { // Get the first part val a = string.substring(0, startIndex) // Get the middle part and do … WebOct 20, 2024 · My question is to replace 1 with so-so, 2 with Bad and 3 with good in 2nd and 3rd columns, and 1 with so-so, 2 with Bad and 3 with good in 5th and 6th column. I try to use num2cell, but cannot find out the way. The output looks like this: Theme. Copy. A = [ 0.5 bad good 2.5 so-so so-so. var str="ArtShare$u002ETotalArtShares" var replace=str.replace ("$u002E", ".") println ("replaced string is "+replace) but output remains same but the for testing i have tried this var str1="ArtShare$u002ETotalArtShares" var replace1=str1.replace ("Total", ".") println ("replaced string is "+replace1) the following is printed kpmg research site